Experiment 6b

Chuong Nguyen U84536721 Post Lab Report Experiment 6 aim out B ( snow points) 1. (15 points) Prepare a table lean the caboodle of the starting materials used and the trade of the dried overlap you collected. mastermind the percent supply for each compound. soften 1| | Part 2| | Material| hail| Material| Amount| KMnO4| 3.7580 g| [NiCl2(PPh3)2]| 0.6026 g| C5H8O2| 16.6 g| NH4SCN| 0.8024 g| Product| | PPh3| 2.0016 g| Mn(acac)3| 6.119 g| Product| | | | [Ni(NCS)2(PPh3)2]| 1.56 g| % turn in= mass of point of intersection/ mass of reactant x 100% Part I 4 KMnO4 + 12 C5H8O2 4 Mn(C5H8O2)3 + 2 K2O + 7 O2 Theoretical yield 0.027 bulwark KMnO4 x 352.26 g/mol Mn(C5H8O2)3 (1:1 ratio) = 9.51 g Mn(C5H8O2)3 0.166 mol C5H8O2 x 352.26 g/mol Mn(C5H8O2)3 (3:1 ratio) = 19.47 g Mn(C5H8O2)3 Limiting reactant KMnO4 Mn(acac)3 %yield = 6.110 g /9.51 g KMnO4 x 100% = 64.25% Part II [NiCl2(PPh3)2] + 2NH4SCN [Ni(NCS)2(PPh3)2] + 2 NH4Cl Theoretical yield .6026 g /259.54g/mol[NiCl 2(PPh3)2] x 304.80 g/mol [Ni(NCS)2(PPh3)2] (1:1 ratio) = 0.7076 g [Ni(NCS)2(PPh3)2] 0.8024 g/ 76.122g/mol NH4SCN x 304.80 g/mol [Ni(NCS)2(PPh3)2] (2:1 ratio) = 1.606 g Limiting reactant [NiCl2(PPh3)2] [Ni(NCS)2(PPh3)2] % yield = 1.56g / 0.7076 g x 100% = 220.

46 % (Excess triphenylphosphine need to account in chemical reply and crossroad yield) 2. (15 points): Prepare a table listing both the data-based magnetic data you obtained for the three compounds you measured. From the data you accumulated, account the gibibyte force ?g of your samples. Convert your gram susceptibility to sub susceptibility, ?M. Compound| L| W| Ro| R| Mn(acac)3| 3.0 cm|! 0.1744 g| -32| 1714| [NiCl2(PPh3)2]| 3.2 cm| 0.1333g| -32| 220| [Ni(NCS)2(PPh3)2]| 4.0 cm| 0.1414 g| -32| -56| ?g = 1.007 (L)(R-R0)/(109)(m) Mn(acac)3= 1.007(3)(1714- (-32)/ (0.1744 x 109) = 3.024 x10-5 [NiCl2(PPh3)2] = 1.007(3.2)(220 (-32)/ (0.1333 x 109) = 6.091 x 10-6 [Ni(NCS)2(PPh3)2] = 1.007(4)(-56 (-32)/ (0.1414 x...If you want to get a in effect(p) essay, allege it on our website: OrderCustomPaper.com

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